Kings XI Punjab beats Royal Challengers Bangalore by 97 runs: IPL 2020

Kings XI Punjab (KXIP) won by 97 runs against Royal Challengers Bangalore (RCB) with the power packed performance  of a KL Rahul 132* — the highest individual IPL score by an Indian.

While Batting first, KXIP scored 206/3 in 20 overs. KL Rahul (132*) and Mayank Agarwal (26) got Punjab off to a fluent start. Yuzvendra Chahal (1/25) got RCB the first breakthrough in the 7th over.

It was Shivam Dube who got them their next two wickets, as Rahul kept losing partners in the middle overs. Rahul went into carnage mode in the death overs, as KXIP scored 206/3 in 20 overs.

RCB, needing 207 to win, were off to a disastrous start in the chase, being reduced to 4/3 in the third over. AB de Villiers (28) and Aaron Finch (20) put on a short rescue act before Punjab’s leg spinners started ruling the roost in the middle overs.

Ravi Bishnoi (3/32) and Murugan Ashwin (3/21) were the pick of the bowlers. RCB were eventually bowled out for 109, suffering their second heaviest defeat of all time in the IPL.